Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.2 Use Combinations and the Binomial Theorem - 10.2 Exercises - Skill Practice - Page 694: 8

Answer

$$\frac{12!}{4!\left(12-4\right)!}=495$$

Work Step by Step

We know the equation for combinations: $$nC_r = \frac{n!}{r!\left(n-r\right)!}$$ Thus, we find: $$\frac{12!}{4!\left(12-4\right)!}=495$$
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