## Algebra 2 (1st Edition)

$792$
We know that if we want to select $r$ objects out of $n$ disregarding the order, we can do this in $_nC_r=\frac{n!}{r!(n-r)!}$ ways. Here we have $3\cdot4=12$ face cards, thus $n=12$ and $r=5$. Thus, the answer is: $_{12}C_5=\frac{12!}{7!5!}=792$