Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.1 Apply the counting Principles and Permutations - 10.1 Exercises - Skill Practice - Page 687: 13

Answer

See below.

Work Step by Step

a) Using the Fundamental Counting Principle the number of possible choices is $26\cdot26\cdot26\cdot26\cdot10\cdot10=45697600$ b) Using the Fundamental Counting Principle and the fact that the number of possible numbers/letters decreases by $1$ if we choose a number/letter, the number of possible choices is $26\cdot25\cdot24\cdot23\cdot10\cdot9=32292000$
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