Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 10 Counting Methods and Probability - 10.1 Apply the counting Principles and Permutations - 10.1 Exercises - Skill Practice - Page 687: 33

Answer

$40320$

Work Step by Step

$_nP_r=\frac{n!}{(n-r)!}$, hence here: $_8P_7=\frac{8!}{(8-7)!}=\frac{8!}{1!}=8!=40320$
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