Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - Chapter Test - Page 65: 16



Work Step by Step

Subtract $12x$ from both sides to get, $-28y=40-12x$ Then divide both sides by -28 and simplify to get, $y=(3x-10)/7$ Plugging in x=6, $y=(18-10)/7$ or 8/7.
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