Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - Chapter Test - Page 65: 31


See below.

Work Step by Step

$V=\frac{1}{3}\pi r^2h\\h=\frac{3V}{\pi r^2}$ Hence here $h=\frac{3(45)}{\pi (2)^2}\approx10.74$
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