Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.7 Solve Absolute Value Equations and Inequalities - 1.7 Exercises - Skill Practice - Page 56: 73


$x\gt\frac{c-b}{a}$ or $x\lt\frac{-c-b}{a}$.

Work Step by Step

$|ax+b|\gt c$ implies $ax+b\gt c\\ax\gt c-b\\x\gt\frac{c-b}{a}$ or $ax+b\lt -c\\ax\lt -c-b\\x\lt\frac{-c-b}{a}$. Thus $x\gt\frac{c-b}{a}$ or $x\lt\frac{-c-b}{a}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.