Algebra 2 (1st Edition)

$p\gt19$ or $p\lt13$.
$|16-p|\gt3$ implies $16-p\gt3\\-p\gt-13\\p\lt13$ or $16-p\lt-3\\-p\lt-19\\p\gt19$. Thus $p\gt19$ or $p\lt13$. Then, by using a graphing utility, the solution set is attached.