Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.7 Solve Absolute Value Equations and Inequalities - 1.7 Exercises - Quiz for Lessons 1.6-1.7 - Page 58: 8


$y=3$ or $y=-5$

Work Step by Step

$|3y+3|=12$ implies $3y+3=12\\3y=9\\y=3$ or $3y+3=-12\\3y=-15\\y=-5$. Here, we don't have extraneous solutions. Thus $y=3$ or $y=-5$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.