Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.7 Solve Absolute Value Equations and Inequalities - 1.7 Exercises - Quiz for Lessons 1.6-1.7 - Page 58: 9

Answer

$z=-\frac{5}{11}$

Work Step by Step

$|2z+5|=-9z$ implies $2z+5=-9z\\5=-11z\\z=-\frac{5}{11}$ or $2z+5=9z\\5=7z\\z=\frac{5}{7}$. Here $z=\frac{5}{7}$ is an extraneous solution. Thus $z=-\frac{5}{11}$.
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