Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.6 Solve Inequalities - 1.6 Exercises - Skill Practice - Page 45: 26

Answer

$x\displaystyle \geq-\frac{1}{2}$ Please see image
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Work Step by Step

$ 11+8x\geq 7\qquad$ ...add $-11$ to each side of the inequality. $ 11+8x-11\geq 7-11\qquad$ ...simplify. $ 8x\geq-4\qquad$ ...divide with $8$. $x\displaystyle \geq-\frac{1}{2}$ The solutions of the given inequality are all real numbers greater than or equal to $-\displaystyle \frac{1}{2}$. Use a solid dot in the graph to indicate $-\displaystyle \frac{1}{2}$ is a solution.
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