Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.3 Solve Linear Equations - Guided Practice for Examples 3,4, and 5 - Page 21: 7



Work Step by Step

$3(x+2)=5(x+4)$ $3x+6=5x+20$ First we move the +6 and +5x to the other side of the equation to isolate the "x" on one side. Moving the +6 and +5x will cause them to become negative. $3x-5x=20-6$ $-2x=14 /(-1)$ $2x=-14$ Then we will divide the equation by 2 so we could get the value of the single "x" $2x=-14 /:7$ $\frac{2}{2}x=-\frac{14}{2}$ $x=-7$ We can also check if our result is correct by substituting our "x" in the original equation... $3(-7+2)=5(-7+4)$ $-21+6=-35+20$ $-15=-15$
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