Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.3 Solve Linear Equations - Guided Practice for Examples 3,4, and 5 - Page 21: 6



Work Step by Step

$10-x=-6x+15$ First we move the +10 and -6x to the other side of the equation to isolate the "x" on one side. Moving the +10 will cause it to become negative while moving -6x will cause it to become positive. $-x+6x=15-10$ $5x=5$ Then we will divide the equation by 5 so we could get the value of the single "x" $5x=5 /:5$ $\frac{5}{5}x=\frac{5}{5}$ $x=1$ We can also check if our result is correct by substituting our "x" in the original equation... $10-1=-6\times1+15$ $9=9$
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