Algebra 2 (1st Edition)

$x=-5$
$-\frac{3}{5}x+1=4$ First we move the +1 to the other side of the equation to isolate the "x" on one side. Moving the +1 will cause it to become negative. $-\frac{3}{5}x=4-1$ $-\frac{3}{5}x=3$ Then we will multiply the equation by -\frac{5}{3} so we could get the value of the single "x" $-\frac{3}{5}x=3 /\times(-\frac{5}{3})$ $-\frac{3}{5}\times(-\frac{5}{3})x=3\times(-\frac{5}{3})$ $x=-5$ We can also check if our result is correct by substituting our "x" in the original equation... $-\frac{3}{5}\times(-5)+1=4$ $3+1=4$ $4=4$