Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - 1.1 Solve Linear Equations - Guided Practice for Examples 1 and 2 - Page 19: 2



Work Step by Step

$7x-41=-13$ First we move the -41 to the other side of the equation to isolate the "x" on one side. Moving the -41 will cause it to become negative. $7x=41-13$ $7x=28$ Then we will divide the equation by 7 so we could get the value of the single "x" $7x=28 /:7$ $\frac{7}{7}x=\frac{28}{7}$ $x=4$ we can also check if our result is correct by substituting our "x" in the original equation... $7\times4-41=-13$ $28=41-13$ $28=28$
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