Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Concept Byte - Finding Roots - Page 554: 6

Answer

Please see the graph. $x=6, -12$
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Work Step by Step

$.5x^2+3x-36=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-3±\sqrt {3^2-4*.5*(-36)})/2*.5$ $x=(-3±\sqrt {9-2*(-36)})/1$ $x=(-3±\sqrt {9-2*(-36)})$ $x=(-3±\sqrt {9+72})$ $x=(-3±\sqrt {81})$ $x=(-3±9)$ $x=-3+9$ $x=6$ $x=-3-9$ $x=-12$
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