Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - Concept Byte - Finding Roots - Page 554: 2

Answer

Please see the graph. $x=3/2, -2$
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Work Step by Step

$2x^2+x-6=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-1±\sqrt {1^2-4*2*(-6)})/2*2$ $x=(-1±\sqrt {1-8*(-6)})/4$ $x=(-1±\sqrt {1+48})/4$ $x=(-1±\sqrt {49})/4$ $x=(-1±7)/4$ $x=(-1+7)/4$ $x=6/4$ $x=3/2$ $x=(-1+7)/4$ $x=(-1-7)/4$ $x=-8/4$ $x=-2$
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