Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Practice and Problem-Solving Exercises - Page 571: 12

$x= -8/3, -12$

$3x^2+44x=-96$ $3x^2+44x+96=-96+96$ $3x^2+44x+96=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-44±\sqrt {44^2-4*3*96})/2*3$ $x=(-44±\sqrt {1936-1152})/6$ $x=(-44±\sqrt {784})/6$ $x=(-44±\sqrt {784})/6$ $x=(-44±28)/6$ $x= (-44+28)/6$ $x = -16/6 = -8/3$ $x=(-44-28)/6$ $x=-72/6 =-12$