Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Practice and Problem-Solving Exercises - Page 571: 10


$x=10, 11/3$

Work Step by Step

$x=(-b±\sqrt {b^2-4ac})/2a$ $3x^2-41x=-110$ $3x^2-41x+110=0$ $x=(-b±\sqrt {b^2-4ac})/2a$ $x=(-(-41)±\sqrt {(-41)^2-4*3*110})/2*3$ $x=(41±\sqrt {1681-1320})/6$ $x=(41±\sqrt {361})/6$ $x=(41±19)/6$ $x=(41+19)/6$ $x=60/6$ $x=10$ $x=(41-19)/6$ $x=(22)/6$ $x=11/3$
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