## Algebra 1

Published by Prentice Hall

# Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 564: 11

#### Answer

$\dfrac{289}{4}$

#### Work Step by Step

$g^2+17g+c$ Compare it with the standard form of quadratic equation $ax^2+bx+c$, we have $a=1, b=17$ It will have discriminant, $d$ with formula : $d=b^2-4ac$ Since, $d=0$ for repeated root of the expression. Therefore, $b^2=4ac$ $\implies$ $c=\dfrac{b^2}{4a}$ To complete the square, plug in $a=1, b=17$. Thus, $c=\dfrac{b^2}{4a}=\dfrac{(17)^2}{4}=\dfrac{289}{4}$

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