# Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 558: 16

The solutions are 5 and 9.

#### Work Step by Step

Factor. $s^2-14s+45=0$ $(s-?)(s-?)=0$ Since the 3rd term is positive and the 2nd term is negative, both factors use subtraction. $(s-5)(s-9)=0$ The zero product property tells us that one of the factors is 0. $s-5=0\ OR\ s-9=0$ $s-5+5=0+5\ OR\ s-9+9=0+9$ $s=5\ OR\ s=9$

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