Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 558: 15

The solutions are -8 and 4.

$g^2+4g-32=0$ $(g+?)(g-?)=0$ Since the 3rd term is negative, the factors have opposite operators. $(g+8)(g-4)=0$ The zero product property tells us that one of the factors is 0. $g+8=0\ OR\ g-4=0$ $g+8-8=0-8\ OR\ g-4+4=0+4$ $g=-8\ OR\ g=4$