Answer
The solutions are $2\frac{2}{3}$ and $3$.
Work Step by Step
Factor the equation, and then use the zero product property. (If the product is 0, one of the factors is zero.)
$3y^2-17y+24=0$
$(3y-?)(y-?)=0$ $\longrightarrow$ The 2nd term is negative and the 3rd is positive, so the second terms in the factored equation are both negative.
$(3y-8)(y-3)=0$
$3y-8=0$ OR $y-3=0$ $\longrightarrow$ solve for t using addition property of equality
$3y-8+8=0+8$ OR $y-3+3=0+3$
$3y=8$ OR $y=3$
$3y\div3=8\div3$ OR $y=3$$\longrightarrow$ use the multiplication property of equality
$y=\frac{8}{3}$ OR $y=3$
$y=2\frac{2}{3}$ OR $y=3$
