Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Lesson Check - Page 557: 2

Answer

The solutions are -9 and 6

Work Step by Step

Factor the equation, then use the zero product property. (If the product is 0, one of the factors is zero.) $t^2+3t-54=0$ $(t+?)(t-?)=0$ $\longrightarrow$The 3rd term is negative, so the factors have opposite operations $(t+9)(t-6)=0$ $t+9=0$ OR $t-6=0$ $\longrightarrow$ solve for t using the addition property of equality $t+9-9=0-9$ OR $t-6+6=0+6$ $t=-9$ OR $t=6$
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