Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-7 Factoring Special Cases: 67

Answer

$(6h-1)^{2}$

Work Step by Step

Given the polynomial $(6h)^{2}$ - 12h + $(1)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ In this polynomial a= 6h and b=1 $(6h)^{2}$ - 2(6h)(1) + $(1)^{2}$ = $(6h-1)^{2}$
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