Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Chapter Review - 8-7 Factoring Special Cases: 66

Answer

$(3p-7)^{2}$

Work Step by Step

Given the polynomial $(3p)^{2}$ - 42p + $(7)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ In this polynomial a= 3p and b=7 $(3p)^{2} - 2(3p)(7) + (7)^{2} =(3p-7)^{2}$
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