Answer
$(p^{3}+20q)^{2}$
Work Step by Step
Given the polynomial
$(p^{3})^{2}$ + 40$p^{3}$q + $(20q)^{2}$
We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of
$a^{2}$ + 2ab + $b^{2}$ = $(a+b)^{2}$
In this polynomial a= $(p^{3}$ and b=20q
$(p^{3}$ + 2($p^{3}$)(20q) + $(20q)^{2}$ = $(p^{3}+20q)^{2}$
