Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 516: 57



Work Step by Step

Given the polynomial $(x^{10})^{2}$ + $4x^{10}y^{5}$ + $(2y^{5})^{2}$ We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of $a^{2}$ + 2ab + $b^{2}$ = $(a+b)^{2}$ In this polynomial a= $x^{10}$ and b=$2y^{5}$ $x^{10}$ + 2($x^{10})(2y^{5}$) + $2y^{5}$ = $(x^{10}+2y^{5})^{2}$
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