Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises: 60

Answer

($p^{3}$ + 18) ($p^{3}$ - 4)

Work Step by Step

Given the polynomial $(p^{3})^{2}$ + 14$p^{3}$ - 72 *** We break of the middle term into two factors that add to give +14 and multiply to give -72. The two numbers are +18 and -4. $(p^{3})^{2}$ + 18$p^{3}$ - 4$p^{3}$ - 72 We take the GCD of the first two and the GCD of the last two terms. $p^{3}$($p^{3}$ + 18) -4 ($p^{3}$ + 18) We take ($p^{3}$ + 18) and factor it out which gives us. ($p^{3}$ + 18) ($p^{3}$ - 4)
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