## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises: 59

#### Answer

($x^{6}$ +5)($x^{6}$ -24)

#### Work Step by Step

Given the polynomial $x^{12}$ - 19$x^{6}$ - 120 We rewrite it as $ax^{2}$ + bx + c $(x^{6})^{2}$ - 19$x^{6}$ - 120 -19= 5-24 -120=5 * -24 *** We break of the middle term into two factors that add to give -19 and multiply to give -24. The two numbers are -24 and +5. $(x^{6})^{2}$ - 24$x^{6}$ + 5$x^{6}$ - 120 We take the GCD of the first two and the GCD of the last two terms. ($x^{6}$ +5)($x^{6}$ -24)

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