## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 490: 45

#### Answer

(a) i. 121 ii. 132 iii. 143 (b) They are the same when x is replaced by 10.

#### Work Step by Step

(a) i. (x+1)(x+1)=$x^{2}$+2x+1 $11\times11$=(10+1)(10+1)=$10^{2}$+2(10)+1=121 ii. (x+1)(x+2)=$x^{2}$+3x+2 $11\times12$=(10+1)(10+2)=$10^{2}$+3(10)+2=132 iii. (x+1)(x+3)=$x^{2}$+4x+3 $11\times13$=(10+1)(10+3)=$10^{2}$+4(10)+3=143 (b) x is replaced by 10 each time so the process is the same

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