Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 490: 34

Answer

$6g^3+11g^2-31g+14$

Work Step by Step

$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3g^2-5g+2$ $\underline{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2g+7}$ $\ \ \ \ \ \ \ \ \ \ \ 21g^2-35g+14\longrightarrow$ multiply by 7 $\underline{6g^3-10g^2+\ \ 4g\ \ \ \ \ \ \ \ \ }\longrightarrow$ multiply by 2g $6g^3+11g^2-31g+14\ \longrightarrow$ combine like terms
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