Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-2 Multiplying and Factoring - Practice and Problem-Solving Exercises - Page 483: 39

Answer

$a^5(31ab^3+63)$

Work Step by Step

Find the greatest common factor. Find the prime factors of each term and multiply the factors that are common to all the terms. $31a^6b^3=31\times\underline a\times\underline a\times\underline a\times\underline a\times\underline a\times a\times b\times b\times b$ $63a^5=63\times\underline a\times\underline a\times\underline a\times\underline a\times\underline a$ GCF$=a\times a\times a\times a\times a=a^5$ Factor the GCF out of each term. Use the factors from each term that are not part of the GCF. $31a^6b^3+63a^5=a^5(31ab^3+63)$
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