## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-2 Multiplying and Factoring - Practice and Problem-Solving Exercises - Page 483: 38

#### Answer

$9m^2n^3(m^2n^2-3)$

#### Work Step by Step

Find the greatest common factor. Find the prime factors of each term and multiply the factors that are common to all the terms. $9m^4n^5=\underline3\times\underline3\times\underline m\times\underline m\times m\times m\times\underline n\times\underline n\times\underline n\times n\times n$ $27m^2n^3=\underline3\times\underline3\times3\times\underline m\times\underline m\times\underline n\times\underline n\times\underline n$ GCF$=3\times3\times m\times m\times n\times n\times n=9m^2n^3$ Factor the GCF out of each term. Use the factors from each term that are not part of the GCF. $9m^4n^5-27m^2n^3=9m^2n^3(m^2n^2-3)$

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