Chapter 7 - Exponents and Exponential Functions - Concept Byte - Page 454: 25

$A(1)= 1.1$ $A(4)= .1375$ $A(8)= .00859375$

$A(1) = 1.1*(.5)^{n-1}$ $A(1) = 1.1*(.5)^{1-1}$ $A(1) = 1.1*(.5)^0$ $A(1) = 1.1*1=1.1$ $A(4) = 1.1*(.5)^{n-1}$ $A(4) = 1.1*(.5)^{4-1}$ $A(4) = 1.1*(.5)^3$ $A(4) = 1.1*.125=.1375$ $A(8) = 1.1*(.5)^{n-1}$ $A(8) = 1.1*(.5)^{8-1}$ $A(8) = 1.1*(.5)^7$ $A(8) = 1.1*.0078125= 0.00859375 $