Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Concept Byte - Page 454: 26

Answer

$A(1)= .25$ $A(4)= -16$ $A(8)= -4096$

Work Step by Step

$A(1)= .25*(-4)^{n-1}$ $A(1)= .25*(-4)^{1-1}$ $A(1)= .25*(-4)^0$ $A(1)= .25*1=.25$ $A(4)= .25*(-4)^{n-1}$ $A(4)= .25*(-4)^{4-1}$ $A(4)= .25*(-4)^3$ $A(4)= .25*-64=-16$ $A(8)= .25*(-4)^{n-1}$ $A(8)= .25*(-4)^{8-1}$ $A(8)= .25*(-4)^7$ $A(8)= .25*-16384=-4096$
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