#### Answer

$h^{26}/32y^9$

#### Work Step by Step

$2y^{-9}h^2(2y^0h^{-4})^{-6}$
$2/y^9*h^2*(2*h^{-4})^{-6}$
$2/y^9*h^2*1/2^6*h^{24}$
$h^{26}/y^9*2^5$
$h^{26}/32y^9$

Published by
Prentice Hall

ISBN 10:
0133500403

ISBN 13:
978-0-13350-040-0

$h^{26}/32y^9$

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