## Algebra 1

Published by Prentice Hall

# Chapter 7 - Exponents and Exponential Functions - Chapter Test - Page 467: 3

#### Answer

$c^2v^9$

#### Work Step by Step

We start with the given expression: $c^3v^9c^{-1}c^0$ We rearrange the expression using the commutative property of multiplication: $c^3c^{-1}c^0v^9$ To multiply powers with the same base, we add the exponents: $c^{3-1+0}v^9=c^2v^9$

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