Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Chapter Review - 7-1 Zero and Negative Exponents: 8

Answer

$\frac{4y^8}{x^2}$

Work Step by Step

We write the expression given as a division problem: $4x^{-2}\div y^{-8}$ The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression: $\frac{4}{x^2}\div\frac{1}{y^8}$ To divide fractions, we multiply by the reciprocal: $\frac{4}{x^2}\times\frac{y^8}{1}$ We multiply the numerators and the denominators: $\frac{4y^8}{x^2}$
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