Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Chapter Review - 7-1 Zero and Negative Exponents: 15

Answer

-$\frac{20}{9}$

Work Step by Step

$\frac{2x}{y^{2}z^{-1}}$, where x = 2, y = -3, z = -5 $\frac{2(2)}{-3^{2}-5^{-1}}$ $\frac{4}{9(-5^{-1})}$ Here, -5$^{-1}$ will be moved to the numerator and the -1 will change to simply 1: $\frac{(4)(-5^{1})}{9}$ = $\frac{(4)(-5)}{9}$ = $\frac{-20}{9}$
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