## Algebra 1

-$\frac{20}{9}$
$\frac{2x}{y^{2}z^{-1}}$, where x = 2, y = -3, z = -5 $\frac{2(2)}{-3^{2}-5^{-1}}$ $\frac{4}{9(-5^{-1})}$ Here, -5$^{-1}$ will be moved to the numerator and the -1 will change to simply 1: $\frac{(4)(-5^{1})}{9}$ = $\frac{(4)(-5)}{9}$ = $\frac{-20}{9}$