Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises: 72

Answer

n has values of 1 and -1.

Work Step by Step

To solve for value of n, we will simplify the equation $n^{-3}$ = $(\frac{1}{5})^{5}$. so $n^{-3}$. = $\frac{1}{n^{3}}$ and $(\frac{1}{5})^{5}$ = $\frac{1}{n^{5}}$ $\frac{1}{n^{3}}$ = $\frac{1}{n^{5}}$. --> Cross Multiply $\frac{n^{5}}{n^{3}}$ = 1 $n^{5-3}$ = 1 $n^{2}$ = 1 n = $\sqrt 1$ n = -1,1 Therefore the values of n are 1 and -1.
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