## Algebra 1

To solve for value of n, we will simplify the equation $n^{-3}$ = $(\frac{1}{5})^{5}$. so $n^{-3}$. = $\frac{1}{n^{3}}$ and $(\frac{1}{5})^{5}$ = $\frac{1}{n^{5}}$ $\frac{1}{n^{3}}$ = $\frac{1}{n^{5}}$. --> Cross Multiply $\frac{n^{5}}{n^{3}}$ = 1 $n^{5-3}$ = 1 $n^{2}$ = 1 n = $\sqrt 1$ n = -1,1 Therefore the values of n are 1 and -1.