#### Answer

$\frac{141}{m^2}$

#### Work Step by Step

We aim for similar denominators so that we can add the two fractions together. We can get our desired result by changing negative exponents into positive exponents by flipping them over the fraction.
$\frac{6}{m^2}+\frac{5m^{-2}}{3^{-3}} = \frac{6}{m^2} + \frac{5*3^3}{m^2} = \frac{6+5*3^3}{m^2} = \frac{141}{m^2}$