# Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 418: 44

$8m^{1/3}\times(m^{1/3}+2)$ $8m^{2/3}+16m^{1/3}$

#### Work Step by Step

1. You are given 8m^(1/3) (m^(1/3)+2) 2. Which is equal to 8m^(1/3)x m^(1/3) + 8m^(1/3)x2 by the law of distribution 3. Remember that when you multiply two exponential term in the form x^n * y^z = (x*y)^(n+z) 4. In this example x=8m, n=1/3, y=m and z=1/3 5. So the first product is 8m^(2/3) 6. The second product is simply 16m^(1/3) 7. And the final answer is their sum

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