#### Answer

$8m^{1/3}\times(m^{1/3}+2)$
$8m^{2/3}+16m^{1/3}$

#### Work Step by Step

1. You are given 8m^(1/3) (m^(1/3)+2)
2. Which is equal to 8m^(1/3)x m^(1/3) + 8m^(1/3)x2 by the law of distribution
3. Remember that when you multiply two exponential term in the form
x^n * y^z = (x*y)^(n+z)
4. In this example x=8m, n=1/3, y=m and z=1/3
5. So the first product is 8m^(2/3)
6. The second product is simply 16m^(1/3)
7. And the final answer is their sum