Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises: 40

Answer

$9$

Work Step by Step

We rewrite the given expression as a division problem: $s^0\div r^{-2}$ The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression: $s^0\div\frac{1}{r^2}$ To divide by a fraction, we multiply by the reciprocal: $s^0\times r^2$ The zero as an exponent rule states that for every nonzero number $a$, $a^0=1$. Since $s^0 = 1$ and the product of $1$ and any number is the original number, we get rid of the $s^0$ term. $r^2$ We plug in the value for $r$: $(-3)^2$ We simplify: $9$
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