Algebra 1

$\frac{5s^2}{t}$
We want to simplify $5s^2t^{-1}$. The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. Thus, we can rewrite $t^{-1}$ as $\frac{1}{t}$ and put the $t$ on the denominator of the expression, giving us $\frac{5s^2}{t}$