Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - Mid-Chapter Quiz - Page 389: 7



Work Step by Step

Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
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