## Algebra 1

$y\lt-3/2*x+3$ $x\leq1$
$x = 1$ and the left side of the line is shaded, so the equation is $x \leq 1$ (0,3) and (2,0) $m = (3-0)/(0-2)$ $m = 3/-2 = -3/2$ $y=mx+b$ $0 = 2*-3/2+b$ $0 = -3 + b$ $0 +3 = -3+b+3$ $3 = b$ $y=-3/2*x+3$ (0,0) is part of the solution set, so the equation is $y\lt-3/2*x+3$