## Algebra 1

$y\geq-2x+2$ $y\lt 3x-2$
(0,2) and (1,0) $m= (2-0)/(0-1)$ $m = 2/-1 = -2$ $y=mx+b$ $0 = -2*1 + b$ $0 = -2+b$ $0+2 = -2+b+2$ $2 = b$ $y=-2x+2$ (0,0) is not in the solution area, so the equation is $y\geq-2x+2$ (1,1) and (2, 4) $m= (4-1)/(2-1)$ $m = 3/1 = 3$ $y=mx+b$ $4=3*2+b$ $4=6+b$ $4-6 = 6+b-6$ $-2 = b$ $y=3x-2$ $y=3x-2$ 0,0) is not in the solution area, so the equation is $y< 3x-2$