Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 379: 43

y=3 z=-1 x=5

Given system of equations 2x-3y+z=0 2x+y+z=12 y-z=4 -1(2x+y+z=12) -2x-y-z=-12 (2x-3y+z)+(-2x-y-z)=0-12 (2x-2x)+(-3y-y)+(z-z)=-12 -4y=-12 => y=3 y-z=4 3-z=4 => z=-1 2x-3(3)-1=0 2x-9-1=0 => 2x=10 => x=5