Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises: 28


The worker has made a mistake because if the equations are true, dolls would have to weigh -3oz each which in reality is not possible.

Work Step by Step

Lets create two equations first. *the number of dolls=d, and the number of polish toys=p* 1. 3d+4p=11 oz 2. 2d+3p=9 oz (we subtracted 1 oz from the weight that the worker measured because the box itself weighs 10z) Then, we multiply the first equation by 2 and the second equation by 3. Now we have: 1. 6d+8p=22 2. 6d+9p=27 Now, we can use elimination as our method for solving this system. We can subtract 6d from both equations. This leads us to the equation: -p=-5 When we solve for p, we p=5. Now when we substitute this value into the first equation to get out weight for dolls, we get 3d+4(5)=11 3d+20=11 (Simplify) 3d=-9 (Subtract 20) d=-3oz (divide by 3) As mentioned above, this answer is not possible due to the fact that the a doll cannot have a negative weight.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.