Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 379: 28


The worker has made a mistake because if the equations are true, dolls would have to weigh -3oz each which in reality is not possible.

Work Step by Step

Lets create two equations first. *the number of dolls=d, and the number of polish toys=p* 1. 3d+4p=11 oz 2. 2d+3p=9 oz (we subtracted 1 oz from the weight that the worker measured because the box itself weighs 10z) Then, we multiply the first equation by 2 and the second equation by 3. Now we have: 1. 6d+8p=22 2. 6d+9p=27 Now, we can use elimination as our method for solving this system. We can subtract 6d from both equations. This leads us to the equation: -p=-5 When we solve for p, we p=5. Now when we substitute this value into the first equation to get out weight for dolls, we get 3d+4(5)=11 3d+20=11 (Simplify) 3d=-9 (Subtract 20) d=-3oz (divide by 3) As mentioned above, this answer is not possible due to the fact that the a doll cannot have a negative weight.
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